X, Y and Z are three points on a map. Y is 85km and on a bearing of 190° from X. Z is on a bearing of 140°, from Y. Z is due south of X. Calculate the distance between X and Z rounded to 1 DP

The distance between X and Z is approximately 95.99 km

Step-by-step explanation:

Given, X, Y and Z are three points on a map. Y is 85km and on a bearing of 190° from X. Z is on a bearing of 140°, from Y. Z is due south of X.

(For Diagram Please Find in Attachment)

Thus, The parameters are

The distance of Y from X = 85 km

The bearing of Y from X = 190°

The bearing of Z from Y = 140°  

The bearing of Z from X = 180°

Now,  

In triangle XYZ, we have

∠YZX = 180° - (130° + 10°) = 40°

Therefore, Apply the sine rule here, we get

(85 km)/sin(40°) = XZ/(sin(130°))

XZ = sin(130°) × (85 km)/sin(30°) ≈ 95.99 km

The distance between X and Z ≈ 95.99 km

Ithink it is 7. 16

A. -10 is the value of x