Can someone help me with a few questions? PLEASE.

.75

p(1)= 47/274= .172

p(2)= 45/274= .164

p(3)= 43/274= .157

p(4)= 45/274= .164

p(5)= 48/274= .175

p(6)= 46/274= .168

.1

Step-by-step explanation:

Not too sure about the first one

Let's start by finding the total area of the cricle

4²π=16π

Then let's find the area of the inside

2²π=4π

subtract these to get the area of the red area

16π-4π=12π

then divide this by the whole circle

12π/16π= .75

2. sum the occurrences:

47+45+43+45+48+46= 274

Then (i think) it's just a matter of division

p(1)= 47/274= .172

p(2)= 45/274= .164

p(3)= 43/274= .157

p(4)= 45/274= .164

p(5)= 48/274= .175

p(6)= 46/274= .168

If two events are independent you can mulitply them to find their intersection

(1/6)*(3/5)= .1

Question 11.2.25

The outer circle has a diameter of 8 feet, which cuts in half to a 4 foot radius.

The area of the outer circle is A = pi*r^2 = pi*4^2 = 16pi

The inner circle has a radius of 2 feet (which is half of the diameter 4 ft), so that would lead to an area of 4pi

The difference in areas is 16pi-4pi = 12pi

The value 12pi is the area of the red ring. Divide this over 16pi to get the probability of landing in the red area

(12pi)/(16pi) = 12/16 = 3/4 = 0.75

Question 11.2.9

Add up everything in the bottom row to get 274

Then divide each value over 274 to get the corresponding probability.

For example, 47/274 = 0.172 represents the approximate probability of rolling a 1 and 45/274 = 0.164 is the approximate probability of rolling a 2 and so on.

You should have these six answers:

Those six values are approximate.

Question 11.3.13

Since A and B are independent, we can say,

P(A and B) = P(A)*P(B)

P(A and B) = (1/6)*(3/5)

P(A and B) = (1*3)/(6*5)

P(A and B) = 3/30

P(A and B) = 1/10

P(A and B) = 0.1

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .