What is the value of z2 if 3z1 = 6 + 18i and z1 + z2 = 5 + 9i?

z2=-3-3i

Step-by-step explanation:

3z1+0z2=6+18i

z1+z2=5+9i (×3)

3z1+3z2=15+27i

3z1+0z2=6+18i (-) =

-3z2=9+9i

z2=-3÷(9+9i)

z2=-3-3i

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form