Sara and jo both ran an 8km race Sarah took 55 mins to run the whole race jo started the race 3 mins later than Sara but caught up when they had both travelled 6 km of Sara and jo both ran at constant speed what is jos speed in 2dp

9.41 km/h

Step-by-step explanation:

The total distance of the race, d = 8 km

The time Sarah took to run the race, t = 55 mins

The time Jo started the race = 3 mins later than Sara

The point Jo caught up with Sarah = 6 km into the race

The rate at which Jo and Sarah ran = Constant speed

The required information = Jo's speed

From the information given, Sarah's speed, v = 8 km/(55 mins) = (8/55) km/min × 60min/h = 96/11 km/h

The time it would take Sarah to run 6 km = 6 km/(8 km/(55 mins)) = 41.25 mins

Given that Jo started 3 minutes late, and they both arrive at 6 km into the race at the same point in time, the time it took Jo to arrive at 6 km into the race = The time it took Sarah - 3 minutes

∴ The time it took Jo to run the 6 km = 41.25 minutes - 3 minutes = 38.25 minutes

Given that Jo ran at a constant speed, and speed = distance/time, we have;

Jo's speed = 6 km/(38.25 min) = 8/51 km/min × 60 min/h = (160/17) km/h ≈ 9.41 km/h.

the correct answer would be:

220 centimeters

to get this you can use the pythagorean theorem

hope this

step-by-step explanation:

c. 6tan80

step-by-step explanation: