If a^2 -b^2 =12 and a-b=4 what is the bay of a +b

a+b = 3

Step-by-step explanation:

a = b+4

a^2 = (b+4)(b+4) = b^2 + 8b +16=-b^2 = 12

8b=-4

b = - 1/2

a = 3.5

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !