This is my last question, I hope to get the right answer
pls and ty :>

Options A ,  D , E

Step-by-step explanation:

Triangle has angles 27° and 45°

The third angle = 180 - 27 - 45 = 108°

Therefore, the angles of ABC are 27° , 45° , 108°

=> ABC is Scalene triangle .

Option A :

Triangle DEF :

       3x + 5x + 12x = 180°

              20x = 180°

               x = 9

Therefore , the angles of DEF = 27° , 45° , 108°

Satisfies

Option B:

Triangle GHI is Isosceles triangle with one angle 108°

But ABC is scalene , therefore not similar.

Does not satisfy.

Option C :

Triangle JKL with one of the angle = 72°

But none of the angles of ABC is equal to 72° .

Therefore, not similar.

Does not satisfy.

Option D :

Triangle MNO have angles 45°  and  108°.

Sum of angles of triangles = 180°

So the third angle of MNO = 27°

Therefore , MNO is similar to ABC.

Satisfy.

Option E:

Angles of triangle PQR are 45° , x° , 4x°

Lets find all the angles .

45 + x + 4x = 180°

5x = 180 - 45

5x = 135

x = 27

Therefore, the angles of PQR = 45° , 27° , 108°

Hence similar to triangle ABC.

Satisfy

Option F :

Angles of triangle STU (5x + 3)°, (9x)° , (21x + 2)°

Sum of the angles => 5x + 3 + 9x + 21x + 3 = 180°

                            => 35x = 180 - 5

                            => 35x = 175

                            => x = 5

Therefore, the angles are

5x + 3 = 5( 5) + 3 = 25 + 3 = 28°

9x =  9 ( 5 ) = 45°

21x + 2 = 21(5) + 2 = 105 + 2  = 107°

The angles are not congruent to the angles of Triangle ABC

does not satisfy.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3