Given that is a standard normal random variable, find for each situation (to 2 decimals). a. The area to the left of is . (Enter negative value as negative number.) b. The area between and is . c. The area between and is . d. The area to the left of is . e. The area to the right of is . (Enter negative value as negative number.)

-0.80

1.66

0.26

2.56

-0.50

Step-by-step explanation:

The values are the probability values either to the right or left of a given z - value ;

The Z - values could be obtained using the standard normal distribution table or a calculator :

Using the Z probability calculator ;

Area to the left of z is 0.2119

1.)

P(z < z) = 0.2119

z = - 0.8

2.)

Area between - z and z = 0.9030

Area to the left of z = 0.9030 plus

Area to the right of z = (1 - 0.9030) / 2 = 0.097/2 = 0.0485

(0.9030 + 0.0485) = 0.9515

P(z < z) = 0.9515

z = 1.66

3.)

Area between - z and z = 0.2052

Area to the left of z = 0.2052 plus

Area to the right of z = (1 - 0.2052) / 2 = 0.7948/2 = 0.3974

(0.2052 + 0.3974) = 0.6026

P(z < z) = 0.6026

z = 0.26

D.)

The area to the left of z is .9948

P(Z < z) = 0.9948

z = 2.562

E.)

The area to the right of z is .6915.

P(Z < z) = 1 - 0.6915

P(Z < z) = 0.3085

z = - 0.5

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

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step-by-step explanation: