The sum of three numbers is 1,116. One of the numbers, k, is 20% less then the sum of
the other two numbers. What is the value of
k?

The value of k is 496

Step-by-step explanation:

let, the other two numbers be x and y

so, (x+y) +k =1116

let the value of (x+y) be 100 so we can assume k to be 20% less of 100 which is 80

so now (x+y) =100(assuming)

k =80(assuming)

now, (x+y) +k =1116 (putting assumed values(

or, 100 + 80 =1116

or, 180 units = 1116

or, 1 unit = 1116/180

.: 1 unit = 6.2

we have assumed value of k to be 80 units previously so now, k = 80 units

or, K =80*6.2 (1 unit =6.2)

.: k = 496

Hope this answer helps you

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2