Find the equation of the line passing through the point that (4,-1)that is parallel to the line 2x-3y=9

y=2/3x-11/3

Step-by-step explanation:

line is parallel so the gradient will be the same ( m=2/3)

using the point (4,-1)

y=2/3x+c

-1=2/3*4+c

-1=8/3+c

c= -11/3

equation ---> y=2/3x-11/3

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step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a