Suppose that Bag 1 contains a red (R), a blue (B) and a white (W) ball, while Bag 2 contains a red (R), a pink (P), a yellow (Y) and a green (G) ball. A game consists of you randomly drawing a ball from each of Bag 1 and Bag 2. (a) What are the 12 outcomes in the sample space S for this experiment? (b) You win the prize of baked goods if you draw at least 1 red ball. List the outcomes in the event that you win that prize, and use them to compute the probability of this event. You should assume that all outcomes in the sample spaces obtained in (a) are equally likely.

1 /2

Step-by-step explanation:

Given :

Bag 1 : Red (R) ; Blue (B) ; White (W)

Bag 2 : Red (R) ; Pink (P) ; Yellow (Y) ; Green (G)

Total number of possible outcomes :

3C1 * 4C1 = 3 * 4 = 12 outcomes

Sample space (S) ;

R B W

R RR RB RW

P PR PB PW

Y YR YB YW

G GR GB GW

To win price of baked goods ; Atleast one red ball must be drawn :

Probability of winning ; P(winning) = required outcome / Total possible outcomes

Required outcome = {RR, RB, RW, PR, YR, GR} = 6

Total possible outcomes = S = 12

P(winning) = 6/12 = 1/2

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}