Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.
After adding B2 to both sides of the equation in step 4, what is the constant on the right side of the equation?

2x^2 + 8x - 12 = 0..divide by 2

x^2 + 4x - 6 = 0

x^2 + 4x = 6...add 4 to both sides of the equation

x^2 + 4x + 4 = 6 + 4

(x + 2)^2 = 10<== ur constant is 10

x + 2 = (+-)sqrt 10

x = -2 (+ - ) sqrt 10

x = -2 + sqrt 10

x = -2 - sqrt 10

i believe the answer is y=0.25x+-3