Write an equation of a line in slope-intercept form that passes through (5, 2) with a slope of -2.

y=-2x+12

Step-by-step explanation:

This is an equation in slope-intercept form:

y=mx+b (where m is the slope and b is the y-intercept)

We are given the slope, -2.

y=-2x+b

We plug in the values (5,2):

2=(-2)*5+b

2=-10+b

b=12

The equation is:

y=-2x+12

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right