After heating a fixed volume of gas at 50 psia from 300° R to 600°R, its pressure will be:

100 psia

Step-by-step explanation:

Applying,

Pressure law,

P/T = P'/T' Equation 1

Where P = initial pressure, P' = Final pressure, T = initial temperature, P' = Final temperature.

make P' the subject of the equation

P' = PT'/T Equation 2

From the question,

Given: P = 50 psia, T = 300°R = (300×5/9)K = 166.66 K, T' = 600°R = (600×5/9)K = 333.33 K

Substitute these values into equation 2

P' = (50×333.33)/166.66

P' ≈ 100 psia

P ≈ 100 psia

2x^2+5x+17

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