For some integer m, every odd integer is of the form a) m b) m + 1 c) 2m d) 2m + 1
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d) 2m + 1

Step-by-step explanation:

'n' is a positive integer which is divided by 2 we get some quotient 'm' and remainder 'r'

Where r = 0 and 1

n = 2m+r (i)

putting r = 0 in eq (i)

n = 2m+0

m = 2m ( Divisible by 2)

It is an even number.

putting r = 1 in eq(i)

n = 2m+1 ( not divisible by 2)

It is an odd number.

So every odd number is in the form of (2m+1). where m is any positive integer.

Every even number is in the form of (2m) where m is any positive integer.

HOPE IT HELPS!!!

d) 2m+1

Step-by-step explanation:

for example:

m be 2 then. 2×2+1=5

m be 3 then. 2×3+1=7

the correct answer is 5 6 and 7