Y-2x-1=0 for -2 ≤ x ≤ 4 . can someone help me graph a straight line for this pls ?​

See the graph below.

It is a straight line segment with endpoints (-2,-3) and (4,9).

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Explanation:

We're told that x is between -2 and 4, including both endpoints.

Let's see what y is when we plug in x = -2

y-2x-1 = 0

y-2(-2)-1 = 0

y+4-1 = 0

y+3 = 0

y = -3

So x = -2 pairs up with y = -3. The point (x,y) = (-2,-3) is on the line. This is the left most endpoint.

Repeat for x = 4 to find what y must be

y-2x-1 = 0

y-2(4)-1 = 0

y-8-1 = 0

y-9 = 0

y = 9

Therefore the point (x,y) = (4,9) is also on the line. It's the right most endpoint

Once we have the two points, we can form the straight line. Simply connect the endpoints mentioned as shown below. We don't extend the line infinitely outwards in both directions because meaning x cannot be smaller than -2, and x cannot be greater than 4 either.

Side note: The given equation is the same as y = 2x+1. It has slope 2 and y intercept 1.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a