Imagine a couple who is ready to start a family. They plan to have exactly four children. Assuming no multiple births (twins, triplets, etc.), use the information provided in Pascal's triangle to determine how many different ways they may have exactly three boys and one girl (regardless of birth order).

4 different ways

Step-by-step explanation:

Total number of children = 4

Distribution of the 4 children :

Number of boys = 3 ; Number of girls = 1

Boy = B ; Girl = G

Possible combinations :

BBBG ; GBBB ; BBGB ; BGBB

From the pascal triangle number of e; number of outcomes = 2

Having exactly 3 boys and 1 girl

Hence, of any of the 4 four total children, 3 must be boys and 1 girl ;

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation: