Determine the degree of the Maclaurin polynomial required for the error in the approximation of the function at the indicatedvalue of x to be less than 0.0001.

Fifth degree polynomial

Step-by-step explanation:

Given data:

e^0.3

error = 0.0001

let the function ; f(x) = e^x

note : x = 0.3

The Maclaurin polynomial f(x) = e^x = 1 + x + x^2 / 2!  + x^3/3!  ---  + ∑ x^n/n!

= 1 + 0.3 + (0.3)^2/2! + (0.3)^3 / 3! --- +  ∑ (0.3)^n/n!

Attached below is the remaining part of the solution

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.