Two men p and q set off from a base camp r prospecting for o, p moves 40km on a bearing 205 degree and q moves 30km on a bearing of 060 degree a. Find the distance of q from p
b. The bearing of q from p​

(a) By cosine rule, /PQ/2=202+152−2×20×15×cos145°

= 400+225−600cos145°

= 625+600×0.8192

= 491.52+625

/PQ/2=1116.52⟹/PQ/=1116.52−−−−−−√=33.41

≊33km ( to the nearest whole number)

(b) By sine rule,

sin<QPR15=sin14533.41

sin<QPR=15sin14533.41

sin<QPR=15×0.573633.41=0.2575

<QPR=14.92°

∴ Bearing of Q from P = 25° + 14.92° = 39.92°.

≊40° (to nearest whole number)

Step-by-step explanation:

hope it helps

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step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1