The tens digit is missing from the three-digit number 8 _ 9. If the tens digit is to be randomly selected from the ten different digits from 0 to 9, what is the probability that the resulting three digit number will be a multiple of 9?

Step-by-step explanation:

Only 1 number works. 1 will make 819 which is divisible by 9.

Since it is 1 of ten numbers can go in the blank, the answer is 1/10 which is 0.1

The 10 number choices are

0,1,2,3,4,5,6,7,8,9

The only one that works is 1 as I've stated.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

he spend 5.1 minutes chatting with his friends.

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5.1