If enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased
between 1950 and 1960, what is the expected
enrollment in 2010?

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

The percentage decrease in between 1950 and 1960 is:

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

Therefore, the expected enrollment in 2010 is 7.875 thousands.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

6 meters

step-by-step explanation: