Suppose speeds of vehicles traveling on a highway have an unknown distribution with mean 63 and standard deviation 4 miles per hour. A sample of size n-44 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?

The standard deviation for the sample mean distribution=0.603

Step-by-step explanation:

We are given that

Mean,

Standard deviation,

n=44

We have to find the standard deviation for the sample mean distribution using  Central Limit Theorem for Means.

Standard deviation for the sample mean distribution

Using the formula

Hence, the standard deviation for the sample mean distribution=0.603

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°