What is the coefficient of x3 in the expansion of (2x−3)5? Group of answer choices

a) -360

b) 720

c) 10

d) -5

e) -120

B) 720.

Step-by-step explanation:

We can use the Binomial Expansion Theorem:

We have the expression:

Therefore, a = 2x, b = -3, and n = 5.

We want to find the coefficient of x³. To get x³, we can cube a. Therefore, we can find our coefficient by letting k = 3. Hence:

Evaluate:

Our answer is B.

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

step-by-step explanation:

se a cavasery6