The length of a rectangle is 6 meters more than its width. The area of the rectangle is 114 square meters. Which of the following quadratic equations represents the area of the rectangle? Suppose x is the width of the rectangle. x 2-6x - 114 = 0​ A) x^2-6x-114=0

B) x^2-6x+114=0

C) x^2+6x+114=0

D) x^2+6x-114=0

last one

Step-by-step explanation:

x = width

x+6 = length

Area = length times width

x(x + 6) = + 6x

+ 6x = 114   (subtract 114 from both sides)

+ 6x -114 = 0

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!