Jane chooses a number X at random from the set of numbers {1,2,3,4}, so that P(X = k) = 1/4 for k = 1,2,3,4.
She then chooses a number Y at random from the subset of numbers {X, ... , 4};
for example, if X = 3, then Y is chosen at random from {3,4}.
(i) Find the joint probability distribution of X and Y and display it in the form of a
two-way table.

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

x = 3 ± √(5+y)

she will sew have sewn five dresses   and be 1/3 done with the sixth one in an hour.

step-by-step explanation:

3/4 of an hour=45 mins

lucy makes 1 dress per 11.25 minutes

45 mins+11.25 mins=56.25 mins

60 mins- 56.25 mins=3.75 mins

3.75 mins is 1/3 of of 11.25 mins

therefore she the other 1/3 would be part of the hour and she will have sewn 5 dresses and begun the sixth.

contact me if you have any questions you are welcome.

y - 25 = 2 ( x - 10 ) should be the answer