A. Verify that y1=e^x and y2=xe^x are solutions of y"-2y'-y=0 on (-infinity, infinity) b. Verify that if c1 and c2 are arbitrary constants then y=e^x(c1+c2x) is a solution of A on (-infinity, infinity)
c. Solve the initial value problem y"-2y'-y=0 y(0)=y y'(0)=4
s. Solve the initial value problem y"-2y'-y=0 y(0)=k0 y'(0)=k1