What are the zeroes of f(x)=(x-7)(x+8)

The zeroes of f(x) = (x-7)(x+8) are 7 and -8.

Step-by-step explanation:

You have to figure out what makes each of the equal to zero.

Step 1 : Make the 2 equations both equal 0.

x-7 = 0

x+8 = 0

Step 2: Solve for x

x-7 = 0

x=7

x+8 = 0

x=-8

So 7 and -8 are both zeroes of this function.

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