A rectangular field 50 meters in width and 120 meters in length is divided into two fields by a diagonal line. What is the length of fence (in meters) required to enclosed one of these fields? A-130
B-170
C-180
D-200
E-300

E. 300

Step-by-step explanation:

A rectangle split in half diagonally yields 2 right triangles.

((For this problem, you are probably supposed to use the pythagorean theorem to find the diagonal length, and then calculate perimeter (length of fence around triangular field). In other words:

(sqrt( (50m)^2 + (120m)^2 )) + 50m + 120m)

))

By definition, the hypotenuse (diagonal) is the longest side.

This means that it must be longer than 120m.

If you add the 2 sides (50m + 120m), you get 170m.

Since the third side has to be longer than 120m, the answer _must_ be over 290m (170m + 120m).

300m is the only answer that fits.

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.