Iliana rotated trapezoid WXYZ 180° about the origin. On a coordinate plane, trapezoid W X Y Z has points (negative 4, 2), (negative 3, 4), (negative 1, 4), (0, 2).

What is the correct set of image points for trapezoid W’X’Y’Z’?

W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2)

Step-by-step explanation:

The vertices of the trapezoid WXYZ are, W(-4, 2), X(-3, 4), Y(-1, 4), and Z(0, 2)

The coordinates of the image following the rotation transformation of the preimage (x, y) 180° about the origin is (-x, -y)

Therefore, following the rotation transformation of trapezoid WXYZ, the coordinates of the image W'X'Y'Z' are given as follows;

W(-4, 2) rotated 180° about the origin gives W'(4, -2)

X(-3, 4) rotated 180° about the origin gives X'(3, -4)

Y(-1, 4) rotated 180° about the origin gives Y'(1, -4)

Z(0, 2) rotated 180° about the origin gives Z'(0, -2)

Therefore, we get;

W'(4, -2), X'(3, -4), Y'(1, -4), Z'(0, -2).

Its A

Step-by-step explanation:

i just took the test.

the 3rd option is right

step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.