The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers.

9514 1404 393

Step-by-step explanation:

Let x represent the even integer between the middle two odd integers. Then the sum of the four odd integers is ...

  (x -3) +(x -1) +(x +1) +(x +3) = -72

  4x = -72

  x = -18

The four integers are -21, -19, -17, -15.

Additional comment

You could let x represent one of the integers. Often, people choose to let it represent the least of them. Then the equation becomes x +(x+2) +(x+4) +(x+6) = -72, so 4x = -84 and x = -21. This introduces a "subtract 12" step in the solution process that is unnecessary if x is chosen to be the average of the integers.

As the average, x is the sum divided by the number of them, so you know x=-72/4 = -18 immediately. Then you just have to find the nearest two odd integers below and above -18. You can do the whole problem mentally.

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y