Given: ∠1 = ∠2; ∠C = ∠D Prove: CX = DX

|
1. ∠ ≅ ∠ 1 2; ∠ ≅ ∠ C D| 1. |
2. AB = AB | 2. |
3. ΔABC ≅ ΔBAD| 3. |
4. AD = BC | 4. |
5. AD = AX + DX | 5. |
6. BC = BX + CX | 6. |
7. AX + DX = BX + CX | 7. |
8. AX = BX | 8. |
If 2 ∠’s of a Δ are =, then the sides opposite them are =
9. DX = CX | 9. |
10. CX = DX | 10.

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

moderators are