a. A simple random sample of size 80 has a mean of 7.31. The population standard deviation is 6.26. Construct a 99% confidence interval for the population mean

5.503484≤x≤9.116516

Step-by-step explanation:

The formula for calculating the CI is expressed as;

CI = x±z*s/√n

x is the mean= 7.31

z is the 99% z-score = 2.58

s is the standard deviation = 6.26

n is the sample size = 80

Substitute into the formula

CI = 7.31± 2.58*6.26/√80

CI = 7.31± 2.58*6.26/8.94

CI = 7.31± (2.58*0.7002)

CI = 7.31±1.806516

CI = (7.31-1.806516, 7.31+1.806516)

CI = (5.503484, 9.116516)

Hence the 99% confidence interval for the population mean is

5.503484≤x≤9.116516

your answer is the frist one

hop i

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: