When dragons on planet Pern lay eggs, the eggs are either green or yellow. The biologists have observed over the years that 21% of the eggs are yellow, and the rest green. Next spring the lead scientist has permission to randomly select 58 of the dragon eggs to incubate. Consider all the possible samples of 58 dragon eggs. What is the usual number of yellow eggs in samples of 58 eggs? (Give answers as SENSIBLE whole numbers.)
minimum usual number of yellow eggs =
maximum usual number of yellow eggs

usual number of yellow eggs = 12

Usual maximum = 21

Usual minimum = 3

Step-by-step explanation:

To solve this, we will use the expected value of a binomial probability.

The formula is;

E(X) = np

Where;

n is sample size

p is probability of success.

We are given;

n = 58

p = 21%

Thus;

usual number of yellow eggs in samples = np = 58 × 21% = 12.18 ≈ 12

From USL(Upper specification limit) and LSL(Lower specification limit) formula, we can find the maximum usual number and minimum usual number of eggs respectively.

Thus;

USL = n(p + 3√(p(1 - p)/n)

USL = 58(0.21 + 3√(0.21(1 - 0.21)/58)

USL = 21.48 ≈ 21

LSL = n(p - 3√(p(1 - p)/n)

LSL = 58(0.21 - 3√(0.21(1 - 0.21)/58)

LSL = 2.87 ≈ 3