In a sample of 500 adults, 345 had children. Construct a 99% confidence interval for the true population proportion of adults with children.

The 99% confidence interval for the true population proportion of adults with children is (0.6367, 0.7433).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

In a sample of 500 adults, 345 had children.

This means that

99% confidence level

So , z is the value of Z that has a p-value of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the true population proportion of adults with children is (0.6367, 0.7433).