A pair of fair dice are rolled. Find the probability of rolling a sum that is a multiple of 3 or a multiple of 4.

0.5555 = 55.55% probability of rolling a sum that is a multiple of 3 or a multiple of 4.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Possible outcomes:

For the pair of dice:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

So 36 total outcomes.

Desired outcomes:

Sum being multiplies of 3 or multiples of 4, so:

(1,2), (1,3), (1,5)

(2,1), (2,2), (2,4), (2,6)

(3,1), (3,3), (3,5), (3,6)

(4,2), (4,4), (4,5)

(5,1), (5,3), (5,4)

(6,2), (6,3), (6,6)

3 + 4 + 4 + 3 + 3 + 3 = 20

Probability:

0.5555 = 55.55% probability of rolling a sum that is a multiple of 3 or a multiple of 4.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1