Successful managers must have personality characteristics often thought of as feminine as well as those thought as masculine. The Ben-Sex-Role Inventory (BSRI) is a personality test that gives separate ratings for female and male stereotypes, both on a scale of 1 to 7. A sample of 144 hotel general managers of three star and four star hotels had mean BSRI masculinity score of 5.91. Assume that the standard deviation masculinity score for all hotel managers is 2.4. What is the margin of error for the sample of hotel managers at 95% confidence?

0.392

Step-by-step explanation:

Given :

Sample size, n = 144

Mean score, = 5.91

Standard deviation, σ = 2.4

The margin of error at 95% confidence, α = 0.05

The margin of error = Zcritical * σ/√n

We use Z because we σ is known

Zcritical at 95% = 1.96

The margin of error = 1.96 * 2.4/√144

The margin of error = 1.96 * 2.4/12

= 1.96 * 0.2

= 0.392

10 you would take 50/ .2

step-by-step explanation:

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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