F(x) = x^2(x + 2) ( x - 2) ( x - 5) has zeroes at x = -2, x = 0, x = 2, and x = 5. What is the sign of f on the interval -2 < x < 5?
A. f is always positive on the interval
B. f is always negative on the interval
C. f is sometimes positive and sometimes negative on the interval

the answer would be c:   ax + b = ax + c

step-by-step explanation:

maybe i can

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

answer: sherk

step-by-step explanation:

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