Which missing piece of information would allow the triangles in the figure to be proven congruent by AAS? A) ∠A ≅ ∠A′

B) BC with a line on top ≅ BC with a line on top of it

C) ∠C ≅ ∠C′

D) AC with a line on top of it ≅ AC with a line on top of it

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  C) ∠C ≅ ∠C′

Step-by-step explanation:

The figures show a marked angle and side. To use AAS, we need another angle that is not adjacent to the marked side. That angle is C (or C'), so we require ...

  ∠C ≅ ∠C′

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this