An 8-kN force is applied over an area of 2 cm^2. What is the stress? 4 MPa

4 kPa

40 kPa

40 MPa

4 Pa

Option a (4 MPa) is the right answer.

Step-by-step explanation:

The given values are:

Force,

F = 8 kN

Area,

A = 2 cm²

The stress will be:

⇒

By substituting the given values, we get

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

3/5

step-by-step explanation:

double number line is not a standard concept, so it must have been defined in your textbook. assume top line is numerator.