2. The following frequency distribution table shows marks obtained in an examina ✓tion. Mark 1 - 10 11 - 20 21 - 30 31 - 40 41 - 50 51 - 60 61 - 70 71 - 80 81 - 90 91 - 100 frequency 4 18 40 45 63 58 44 32 7 4 .Calculate the mean mark. ​

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

my answer is$ 12

step-by-step explanation:

because 15 -2=12

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %