What are the x-int of the parabola graphed below?
2
N
O x=2 and x=4
Ox=0 and x=4
O
x=1 and x=0
О
X=1 and x=2

Step-by-step explanation:

The x-intercepts exist where y is equal to 0...which is ON the x-axis. Hence, the name "x-intercept". These are caled zeros, solutions, and roots. This parabola goes through the x-axis at x = 0 and x = 4. It is at both of these locations where the y-coordinate is 0.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

answer: answer is b.

[m < b = 120º]

step-by-step explanation: