The diagram shows a straight line. l find the equation of line l find the equation of the line perpendicular to line l that passes through 9.3

First find the gradient of L.

-6÷3=-2

gradients of perpendicular lines multiply together to give -1.

(-2)×1/2=-1

m=1/2 or 0.5

y=0.5x-1.5

$32,660

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.