The speed of train A is 6 mph slower than the speed of train B. Train A travels 190 miles in the same time it takes train B to travel 220 miles. Find the speed of each train.

train A=38mph train B=44mph

Step-by-step explanation:

Setting up a table:

         s            t           d

A     x            190/x    190

B    x+6      220/x+6  220

Train A was 6mph slower as shown in the table, so to make it easier, train a is identified as x, train b would be x+6

Their distances are put in their respective column.

You find time from distance divided by speed.

So time would be written as such.

Since you know they take the same amount of time, for the equation, you connect them with an equal sign. Cross multiply to something like:

190(x+6)=220x

190x+1140=220x

1140=30x

x=38

You plug this in and get the speed for train A as 38, and train B as 44.

Hope this helps ^^