1. triangle ABC and triangle DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39). If AD is extended to intersect BC at P, show that CEI (i) triangle ABD= triangle ACD ( (ii) triangle ABP triangle ACP (iii) AP bisects < A as well as < D. (iv) AP is the perpendicular bisector of BC.​