Given: AB intersects DĖ at point C. What is the missing reason in step 5?
Prove: ZDCB ZECA
O linear pair postulate
O given
D
O definition of complementary angles
O congruent complements theorem
С
B
Reasons
1
given
AN
Statements
1
AB intersects DE at point C
2 DCB and BCE are a linear pair
GDCB is supp 10 BCE
ZBCE and ECA are a linear pair
5 _BCE is supp to ZECA
6 DCB = LECA
2 def, of lin pr
3 linear pair post
4 def of lin pr
5 2
6 Supp. thm
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b

step-by-step explanation:

calculate the scale factor as the ratio of corresponding sides, image to original, that is

scale factor = = = = 1

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)