What is the approximate area of the shaded region under the standard normal curve below? Use the portion of the standard normal table given to help answer the question. a. 0.02
b. 0.14
c.0.34
d.0.84

You want to find Pr[-2 < Z < -1].

The table tells you that

• Pr[Z < 0] = 0.5000

• Pr[Z < 1.00] = 0.8412

• Pr[Z < 2.00] = 0.9772

• Pr[Z < 3.00] = 0.9987

We have

Pr[-2 < Z < -1] = Pr[Z < -1] - Pr[Z < -2]

(because the distribution of Z is continuous)

… = Pr[Z > 1] - Pr[Z > 2]

(by symmetry of the distribution about its mean)

… = (1 - Pr[Z < 1]) - (1 - Pr[Z < 2])

(by definition of complement)

… = Pr[Z < 2] - Pr[Z < 1]

… = 0.9772 - 0.8412

… = 0.1360 ≈ 0.14 … … … (B)

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation: