Jerome is writing a coordinate proof to show that the midsegment of a trapezoid is parallel to its bases. He starts by assigning coordinates as given, where RS¯¯¯¯¯ is the midsegment of trapezoid KLMN. Trapezoid K L M N on the coordinate plane. The vertices of the trapezoid are K begin ordered pair 0 comma 0 end ordered pair, L begin ordered pair 2a comma 0 end ordered pair, M begin ordered pair 2d comma 2c end ordered pair, and N begin ordered pair 2b comma 2c end ordered pair. Segment R S is drawn with point R on segment K N and point S on segment L M. Drag and drop the correct answers to complete the proof. Since RS¯¯¯¯¯ is the midsegment of trapezoid KLMN, the coordinates of R are (Response area, Response area) and the coordinates of S are (a + d, c). The slope of KL¯¯¯¯¯ is 0. The slope of RS¯¯¯¯¯is 0. The slope of NM¯¯¯¯¯¯¯ is Response area. The slope of each segment is 0; therefore, the midsegment is parallel to the bases.

In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000