Second time I’ve posted this. Please help!! :)

-2 is an extraneous solution because it creates 0 in the denominator.

There is one acceptable solution to the equation

Step-by-step explanation:

x² + 5x + 6 = x² + 2x + 3x + 6

                  = x(x + 2) + 3(x + 2)

                  = (x + 2)(x + 3)

x² + 3x + 2 = 5x + 10

x² + 3x - 5x + 2 - 10 = 0

x² - 2x - 8 = 0

x² + 2x - 4x - 8 = 0

x(x + 2) - 4(x + 2) = 0

(x + 2)(x - 4) = 0

x +2 = 0    or x - 4 = 0

x =  - 2    or x = 4

b and c

step-by-step explanation:

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)