Please help me Q 11 -18

i did problems 12 and 13

Step-by-step explanation:

these problems are known as composite functions. in order to solve them, you will substitute 1 expression into the 'x' or any variable in the first equation.

problem 12:

h(n) = n^2 - 2n

g(n) = 3n + 1

substitute 3n + 1 into the 'n's of h's function

(3n+1)^2 -2(3n+1)

9n^2 + 6n + 1 - 6n - 2

9n^2 - 1

problem 13:

g(a) = a^2 - 3

h(a) = 3a

substitute 3a into 'a' of g's function :

(3a)^2 - 3

9a^2 - 3

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

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