What else would need to be congruent to show that AABC=A DEF by the AAS theorem?
8
Given:
ܪ ܂
ZA ZD
2B RPE
F
A. AC = DF
B. 2Cz2p
C. BE ZE
D. BC = DF

D. AC ≅ DF

Step-by-step explanation:

According to the AAS Theorem, two triangles are considered congruent to each other when two angles and a mon-included side of one triangle are congruent to two corresponding angles and a corresponding non-included side of the other.

Thus, in the diagram given:

<A and <B in ∆ABC are congruent to corresponding angles <D and <E in ∆DEF.

The only condition left to be met before we can conclude that both triangles are congruent by the AAS Theorem is for a mon-included side AC to be congruent to corresponding non-included side DF.

So, AC ≅ DF is what is needed to make both triangles congruent.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)