2) Find the sum of the first 50 terms of the following series, to the nearest integer.
6, 10, 14,...

The sum of the first 50 is 5200

Step-by-step explanation:The given sequence is a linear sequence.

So, first we calculate the common difference

d=t2-t1

d=10-6=4

The sum of the first 50 terms is then calculated using: sorry it wont let me copy and paste my explo and im lazy

5,200

Step-by-step explanation:

6, 10, 14, ...

Sum = [ number of terms(first term+last term) ] / 2

-we know there are 50 terms

-we now the first term is 6

-we need to find the last term

last term = first term + (n-1)* difference between first and second term

last term = 6 + (50-1) * (10-6)

last term = 6 + 49*4 = 202

Sum = [ number of terms(first term+last term) ] / 2

Sum = [ 50 ( 6 + 202) ] / 2 = 5,200

the answer is d. (1.2, -4.7) on edgn

hope this !